Solve tasks
11 USD Task 1
It is necessary to calculate the minimum number of IPs.
There are n people, and each needs m IP addresses. The intersection of IP addresses between any two people must not exceed 50% (i.e., if m=2, then the intersection by IP can only be 1 address).
There are n people, and each needs m IP addresses. The intersection of IP addresses between any two people must not exceed 33.3% (i.e., if m=3, then the intersection by IP can only be 1 address).
Simple examples:
1. there are 2 people and they need to be assigned 2 IPs, the intersection of their IPs is no more than 50%
Person 1: IP1, IP2
Person 2: IP1, IP3
Answer: 3
2. there are 3 people and they need to be assigned 2 IPs and the intersection is no more than 50%
Person 1: IP1, IP2
Person 2: IP1, IP3
Person 3: IP2, IP3
Answer: 3
A formula is needed for calculation.
Task 2
2. There are D number of IP addresses, there are n people, each person has a different number of IP addresses (from 1 to m, D>=m), there is an intersection coefficient k.
How many ways can m addresses be extracted from D with an intersection coefficient k?
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В каком формате должно быть решение?
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Привіт потрібно просто формули із розрахунками?
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Andrey Sivenko PAS web
нужны формулы
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Есть ли у вас еще есть тестовые примеры, чтоб проверить?
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Andrey Sivenko PAS web
да, те что я посчитал перебором без формулы
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Для четного m, если у каждой пары только 1 общий адрес, начиная с n >= m(m+1)/2 все адреса становятся shared, а их минимальное количество x = n.
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