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CLI program in C++ that uses System Informer Lib

128 USD

Client's review of cooperation with Petro Nikolenko

Quality
Professionalism
Cost
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Done a good job, delivered the software as requested. I would like to work with him again.

Freelancer's review of cooperation with Yahia Hamza

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It was a great experience.

  1. 505    4  0
    Winning proposal6 days128 USD

    I have experience with WinAPI C++ coding. I can to help you with this task.

  2. 1494    10  0
    10 days233 USD

    I can help you write this lib on C/C++ CLI. Write me in PM

  3. 1 proposal concealed
  • Oleksii Mamontov
    27 April 2024, 20:22 |

    Sage chat bot

    Для получения списка всех процессов, работающих в операционной системе Windows, вы можете использовать функции из библиотеки Windows API. Вот пример кода на C++, который выполняет это:


    cpp

    Copy

    #include <iostream>

    #include <windows.h>

    #include <tlhelp32.h>


    int main() {

        // Получаем снимок текущих процессов

        HANDLE snapshot = CreateToolhelp32Snapshot(TH32CS_SNAPPROCESS, 0);

        if (snapshot == INVALID_HANDLE_VALUE) {

            std::cerr << "Не удалось получить снимок процессов." << std::endl;

            return 1;

        }


        // Инициализируем структуру процесса

        PROCESSENTRY32 processEntry;

        processEntry.dwSize = sizeof(PROCESSENTRY32);


        // Получаем первый процесс в снимке

        if (!Process32First(snapshot, &processEntry)) {

            std::cerr << "Не удалось получить информацию о первом процессе." << std::endl;

            CloseHandle(snapshot);

            return 1;

        }


        // Перебираем все процессы и выводим информацию о них

        std::cout << "Список процессов:" << std::endl;

        do {

            std::cout << "Идентификатор процесса: " << processEntry.th32ProcessID << std::endl;

            std::cout << "Имя процесса: " << processEntry.szExeFile << std::endl;

            std::cout << std::endl;

        } while (Process32Next(snapshot, &processEntry));


        // Закрываем дескриптор снимка процессов

        CloseHandle(snapshot);


        return 0;

    }

    Этот код использует функции CreateToolhelp32Snapshot, Process32First и Process32Next для получения информации о процессах и их перебора. Он выводит идентификатор и имя каждого процесса на консоль.


    Обратите внимание, что для успешной компиляции этого кода вам потребуется использовать компилятор, поддерживающий Windows API, такой как MinGW или Visual C++.

  • Yahia Hamza
    27 April 2024, 20:33 |

    this is the output

    List of processes:

    Process ID: 0

    Process name: 0000001E2C2FF6AC


    Process ID: 4

    Process name: 0000001E2C2FF6AC


    Process ID: 244

    Process name: 0000001E2C2FF6AC


    Process ID: 912

    Process name: 0000001E2C2FF6AC


    Process ID: 1128

    Process name: 0000001E2C2FF6AC


    Process ID: 1444

    Process name: 0000001E2C2FF6AC


    Process ID: 1452

    Process name: 0000001E2C2FF6AC


    Process ID: 1516

    Process name: 0000001E2C2FF6AC


    Process ID: 1524

    Process name: 0000001E2C2FF6AC


    Process ID: 1660

    Process name: 0000001E2C2FF6AC


    Process ID: 1688

    Process name: 0000001E2C2FF6AC



  • Oleksii Mamontov
    27 April 2024, 20:40 |

    https://poe.com/  Sage СhatBot ))

    Задавайте вопросы и получите ответы)

  • Yevhenii Z.
    27 April 2024, 21:40 |

    Бот конечно молодец, только вывод сильно отличается от требуемого

  • Yahia Hamza
    27 April 2024, 21:49 |

    This task can not be done with a bot 😕 

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Client
Yahia Hamza
Germany Berlin  12  0
Project published
2 years back
2 years
77 views