Strings and Strings
7 USD The wheel is given points A and B. Find the geometric location of points M, for each of which MA·MB = MN2, where MN is touching the wheel in point N.
and disconnection.
From the knowledge of the properties of the silk and touching arises that m.t. It is the point of AM1 and BM2.
If the MA radius crosses a circle in point C, then the MA · MB = MN 2 and the MA · MC = MN 2. From there MB = MS, that is, the MBC triangle is equal and .
The difference is constant. I mean Mr. T. They also satisfy the points that are the heights of the equal corners that are based on the AB section of the given length, i.e. the points of the hole (without its ends) of the second hole that passes through the points A, B, M.
Thus, the M.T. is looking for. - the combination of the AM1, BM2 and the AMB lumens, located outside the given circle.
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Client's review of cooperation with Dmitriy Musenko
Strings and StringsThank you for the quick and efficient task.
Freelancer's review of cooperation with Bogdan M.
Strings and StringsI am very grateful to Bogdan for the fruitful and exciting cooperation, not only strengthened by clearly formulated requests and tasks, but also by practically instant and incredibly pleasant contact.
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Winning proposal1 day7 USD
330 5 0 Winning proposal1 day7 USD
Good Morning Andrei. Get acquainted with your project and ready to approach it with maximum responsibility, and implement in the shortest time possible, but for the beginningwill to discuss the details of your project.
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