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Freelance projects

Official website of Laravel 9

Website Maintenance — incorrectly specified categories?

Project translated automatically. Log in or register, to view the original 1 . The menu points are removed from the base in the loop and you need to light in the class="active" menu only one active menu point. It is now in this way. @ foreach ($posts as $post) {{ $post->title }} by endforeach Domain of Cinema in LS 2nd The mobile version of the site has a search window for posts. You need to set out the posts found on the site. Search for frontend On the input width screen ('search'); // Search in the title and body columns from the posts table $posts = Post::translatedIn() • Published () ->whereTranslationLike('title', "%{$search}%") ->orWhereTranslationLike('text', "%{$search}%") “Paginate” (8) Return the search view with the resluts compacted return view ('search', compact ('posts') Search Results - Cinema in Ls

Proposals 6 Discussions 9

Dmitry Bondar

12 1

Projects 13
Rating -
Rating 648

Budget: 500 UAH Deadline: 1 day

There is nothing difficult in the submitted tasks - in the comments to everything answered

Aleksey L.

25 2

Projects 27
Rating -
Rating 1 126

Budget: 1000 UAH Deadline: 1 day

A good day.
I am specializing in Laravel, I work with the front.
Examples of portfolio.

Aleksey Rill

35 1

Projects 24
Rating -
Rating 266

Budget: 1000 UAH Deadline: 1 day

Good morning, I have experience working with Laravel, I could do it.

...
Limit to symbols, the shortness of the sister of talent?

Vitalii K

3 0

Projects 3
Rating -
Rating 175

Budget: 2000 UAH Deadline: 2 days

Good day .

I have experience working with Laravel and ready to perform the task quickly and quality.

The list does not show proposals concealed by the client or freelancer with a Plus profile, as well as proposals violating rules

Dmitry Bondar 13 December 2022

в 1 сделайте следующее:
<li @if(Route::is('blog.show')) class="active" @endif><a href="{{ route('blog.show', $post->slug) }}">{{ $post->title }}</a></li>

Boris I.

13 December 2022

Попробовал, подсвечиваются сразу все меню постов

в базе еще есть post_id поле. Спроси - может как-то с post_id связать ?

Dmitry Bondar 13 December 2022

попробуй тогда сравнивать текущий урл с роутами:
// Получить текущий URL без строки запроса
url()->current();
// Получить текущий URL, включая строку запроса
url()->full();

Boris I.

13 December 2022

Можете полную строку дать? Как правильно прописать?

Dmitry Bondar 13 December 2022

<li @if(url()->current() == route('blog.show', $post->slug) || url()->full() == route('blog.show', $post->slug)) class="active" @endif><a href="{{ route('blog.show', $post->slug) }}">{{ $post->title }}</a></li>

Boris I.

13 December 2022

Дмитрий, спасибо, Ваш способ помог.

Предлагаю за решению этой задачи двести грн + оцените, пожалуйста, фикс с поиском.

Готовы работать пошагово, есть еще задачи.

Dmitry Bondar 13 December 2022

не совсем понял что нужно в поиске, с запросами ->orWhere нужно быть очень осторожно. Если в методах translatedIn() или published() есть условие ->where, то оно уже работать не будет!!!
нужно объединять условия в группы типа:
->where(function ($query) {
$query->where('votes', '>', 100)
->orWhere('title', '=', 'Admin');
})

Boris I.

13 December 2022

Нужно сделать поиск по постам по трем полям в базе

->whereTranslationLike('title', "%{$search}%")
->orWhereTranslationLike('short_text', "%{$search}%")
->orWhereTranslationLike('text', "%{$search}%")

Dmitry Bondar 13 December 2022

запрос именно для поиска (т.е. после выборки активностей и прочих ограничителей) будет выглядеть так:
->where(function ($query) use ($search) {
    $query->where('title','LIKE', "%{$search}%")
        ->orWhere('short_text','LIKE', "%{$search}%")
        ->orWhere('text','LIKE', "%{$search}%");
})

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