Матлаб
11 USDнужно для личных целей, не понимаю синтаксиса, а курс надо пройти.
задача:
3. To nd a root of the relationship f(x) = 0:01x3 100x30, we can rearrange the equation in the form
of x = g(x) where g(x) = (0:01x330)=100. This is known as xed point iteration and can be initiated
from a seed (guess) value.
(a) Plot the line y = x, and the formula y = g(x). Note that their points of intersection represent
roots of f(x).
(b) Using a seed value of x = 20, create a loop to first found g(x) from the seed value, and then update
x = g(x). The next iteration repeats the process by using the newly found x value to compute
g(x). Apply only 10 iterations and tabulate the values of x, g(x) and f(x) for all iterations.
(c) Repeat part (b) using a new seed value of x = -100 and tabulate your results.
(d) Comment on the eаect of using the two seed values on the results.
задачки 3, 4, 5.
Applications 1
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Не до конца понимаю задачу.
Вам просто нужен код с решениями данных задач? Или же Вам для изучения необходимы объяснения с примерами похожих заданий?
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нужно и то, и другое. сначала код для поставленных задач, а потом хотя бы пару примеров, как были решены другие задачи. пока за эту "работу" взялись, у меня будет еще одна на следующей неделе.
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